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It says math and physics on the forum head...so I figure there must be at least some ppl who know what they're talking about. Why did you even bother posting. Bah.

Nobody? I really need help, any help is good. I just need to know if I'm on the right track. :yikes:

Hey guys,
here's the question:
You are an athlete on the high bar in a fully extended position 180 degrees from the right horizontal.
My weight: 667.08N
Center of mass:80.5cm
Radius of...

Hi,
Ok so we were told to find our center of mass using the reaction board method, but modified. We just do a pushup position with our hands on a scale, I have a electronic one and toes on the...

Please anyone with any hints? It's really important.

Ok,
I had to test my maximum vertical jump. I did three trials and here's what I got:
Maximum standing height (ie without jumping reaching with one hand) = 221.5 cm
Maximum jumping height with...

Ah yes, the way you did it is actually right. I went to my prof. It was actually an error on my part, I failed to realize that I had to separate the component forces into Fx and Fy, my bad. Thanks...

Ok, here's the problem:
Hey,
Ok here's the problem.
A house has a roof with the dimensions in drawing. Determine the magnitude and direction of the net force that the atmosphere applies to...

I think if we measure antinodes it's half of a full wavelength?
Look at pic?

Are you sure? The antinodes are the highest point of a wave right, if we were to measure from node to node, the points of no vibration then it'll be one lambda?

I think you mean 1/3 = time, 3 hz is freq. Ok, the wavelength is equal to ~0.79m. Since the distance isn't really one lambda, but lambda/2, so the distance travelled is ~0.390m. Yes, now I can use...

Hmm, I might be able to find the distance betwen the two antinodes, it does say it goes from loudsoftlound. So antinodenodeantinode, and antinode is where it peaks. But find the wavelength...

Hey,
My question:
Two loudspeakers face each other, vibrate in phase, and produce identical 440Hz tones. A listener walks from one speaker toward the other at a constant speed and hears the...

Well, with much thought...I figure ok since the mill has 16 blades/gaps, all equal, the theta or angle would be 2pie/16 or pie/8. Using theta=wt, I found the time to be 0.312s.
next, I just used...


Hey, any ideas on this double starred, hard question :(
A golf ball passing trhough a windmill at a miniature golf course. The windmill has 8 blades and rotates at an angular speed of 1.25 rad/s...

Ok, I figured out what I did wrong. The quadratic eq for one thing I'm missing a b^2 in the top part. Ok, so now I get 7.0m/s and 4.0m/s. These answers makes more sense because if it is elastic then...

Ok here's two problems that I have attempted to solve, and quite succesfully, but I need one you to check the work. Suggestions to anyone question is great and well appreciated.
1)A mine car,...

BTW, Thanks for the Help!

wow, that looks complicated lol.
Ok, does this way work?
uphill:mgsin@F+(E+1298N)
downhill: mgsinE+F
solve for E in bottom and sub into uphill equation.
E=mgsin@+F

Slosh, help me lol, I'm out of ideas

Ok is this way possible?
Ok so let me see:
P=FV
P(uphill)=mgsin@ +F(friction)
P(downhill)=mgsin@F(friction)
ok so I subtract them:

why did you include 19000 in there might I ask? W acts in the vertical, how does that influence the horizontal forces?

ok so far so good. Ok so, I don't have F, E and @ variables but I have mg which gives me N?
ok so F=E+X
F=mgsin@
so, mgsin@=E+1298. I can't solve for E, I don't have @.
Ok, so...

Well as far as understanding your diagram, I'm on the mark. But as for your equations, I'm lost lol. But thanks for the help, I'm sure once I get my sleep/early morning coffee I'll be able to figure...

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