this gave me an idea... since I'm only looking at one quadrant, what if I took the radius of the circle needed to touch both (x,y) and (y,x)...I mean, just the hypotenuse of a right triangle touching either point... plus the sine times cosine of the vector... wouldn't that give a unique identifier?
like...
(x^2+y^2)+( SIN(ATAN(x/y)) * COS(ATAN(x/y)) )
everything right of the decimal point would be descriptive of the vector, unique because of the phase difference and because we're only dealing with one quadrant... everything left of the decimal point would be a whole integer hypotenuse^2...
unfortunately no, it does not depend on how much of full plane you use, as long as there's infinite amount of numbers. take a look at the graph, and especially contour plot of your function below - every curve on contour plot represents a set of (x,y) points that evaluate in the same value.
yes... I know they're circular... but is there ever more than one pair of whole integers described? I mean, could any two integers produce the same result as any other two integers, so that
[ f(x1,y1) , f(y1,x1) ] == [ f(x2,y2) , f(y2,x2) ] ?
If not... then this would satisfy to give a unique identifier of two ID's combined...
aah, integers - I kinda thought of any real numbers. it might work with integers, indeed, maybe run 100000x100000 check loop? if you have a couple of hours to waste
It works, at least to 1000 x 1000...and I don't see why it wouldn't work infinitely =)
It also works to produce unique identifiers for reversible combinations of more than two integers, like this:
[unique floating id from a set of three integers]
(a^2+b^2+c^2)+( sin(atan(a/b))*cos(atan(a/b))*sin(atan(a/c))*cos(atan(a/c))*sin(atan(b/c))*cos(atan(b/c)) )
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