eval

[reemo]

i have:

var city = london;
var citytext = eval(city+"text");


that works well.

now i have

var city = londontext;
var city = eval(city-"text");

that doesnt give me the result i was looking for.

is there a way to do this?

[Jayhoo]

you cant use maths with Strings
The + when used with a string "concatenates" them togther, basically sticks them together i.e.

trace("1"+"2") // gives "12" not 3

You need to use some string manipulation code to get what you want.
The below code extracts the strings from the instance of "London" to the end of the string and vice versa


myString="helloLondon"


Temp=myString.substr( myString.indexOf( "London", 0 ), myString.length )

trace(Temp)

Temp=myString.substr( 0, myString.indexOf( "London", 0 ) )


trace(Temp)

Hope this helps, could be worth looking for string manipulation tutorials if the above code doesnt make sense.

[enemem]

also, eval is a bit dated now. Use array notation instead:

eval(city + "text")

becomes:

this[city + "text"]

and

eval ("_root." + myVariable + "._alpha")

becomes:

_root[myVariable]._alpha

Hope that makes some sense - n.

[reemo]

thanx, your code did work- but i am not inputting the actual sting so it didnt work when i wrote the folowing:

myString=_name;

suffix=myString.substr( myString.indexOf( "text", 0 ), myString.length );
trace(suffix);

Temp=myString.substr( 0, myString.indexOf( "text", 0 ) );
trace(Temp);


var city = _parent.vienna;
var citytext = eval(city+"text");
var citybg = eval(city+"bg");

_parent.highlight(city,citytext,citybg);