Same entitled movieclips hittesting each other?

[Holsey]

Sort of a hard thing to explain, but i have a database that holds the enemies that are generated within the game.

for(var i = 0; i < meepsArray.length; i++)
	{
if(["meep"+i].hitTest(["meep"+i])){
    trace("success")
    }
}

This is the only way i can think of doing it. If meep(any number) hits another one, execute code. This, however, does not work. I don't see why because if i use a different array, say:

if(["blah"+i].hitTest(["meep"+i])){
    trace("success")
    }

That seems to work. How can i make it so they can hittest each other? In the long wrong, i'm just going to use a distance formula to execute the code since hitTest isn't the most accurate thing in the world. But for testing purposes i've been using hittest.

-Holsey

[koenahn]

Hi.

You wrote this code:

for(var i = 0; i < meepsArray.length; i++)
{
if(["meep"+i].hitTest(["meep"+i])){
trace("success")
}
}

Let's assume the array length is 3. Then your code will do exactly this:

if (meep0.hitTest(meep0)){trace('success');}
if (meep1.hitTest(meep1)){trace('success');}
if (meep2.hitTest(meep2)){trace('success');}
if (meep3.hitTest(meep3)){trace('success');}

But that is not what you want. What you want is this:

if (meep0.hitTest(meep1)){trace('success');}
if (meep0.hitTest(meep2)){trace('success');}
if (meep0.hitTest(meep3)){trace('success');}

if (meep1.hitTest(meep0)){trace('success');}
if (meep1.hitTest(meep2)){trace('success');}
if (meep1.hitTest(meep3)){trace('success');}

if (meep2.hitTest(meep0)){trace('success');}
if (meep2.hitTest(meep1)){trace('success');}
if (meep2.hitTest(meep3)){trace('success');}

if (meep3.hitTest(meep0)){trace('success');}
if (meep3.hitTest(meep1)){trace('success');}
if (meep3.hitTest(meep2)){trace('success');}


Am I right? Then you need this:

for(var i = 0; i < meepsArray.length; i++){
for(var j = 0; j < meepsArray.length; j++){
if(["meep"+i].hitTest(["meep"+j])){
trace("success")
}
}
}

[Holsey]

Hi.

You wrote this code:



Let's assume the array length is 3. Then your code will do exactly this:

if (meep0.hitTest(meep0)){trace('success');}
if (meep1.hitTest(meep1)){trace('success');}
if (meep2.hitTest(meep2)){trace('success');}
if (meep3.hitTest(meep3)){trace('success');}

But that is not what you want. What you want is this:

if (meep0.hitTest(meep1)){trace('success');}
if (meep0.hitTest(meep2)){trace('success');}
if (meep0.hitTest(meep3)){trace('success');}

if (meep1.hitTest(meep0)){trace('success');}
if (meep1.hitTest(meep2)){trace('success');}
if (meep1.hitTest(meep3)){trace('success');}

if (meep2.hitTest(meep0)){trace('success');}
if (meep2.hitTest(meep1)){trace('success');}
if (meep2.hitTest(meep3)){trace('success');}

if (meep3.hitTest(meep0)){trace('success');}
if (meep3.hitTest(meep1)){trace('success');}
if (meep3.hitTest(meep2)){trace('success');}


Am I right? Then you need this:

My code, nor yours, works at all. I don't understand why. The one you've presented to me should actually work, but i'm having no luck.

[koenahn]

for(var i = 0; i < meepsArray.length; i++){
trace(["meep"+i]._x);
}

Try running this. If it keeps saying undefined, maybe the names of your meep instances aren't "meep0" up to and including "meep"+meepsArray.length. In that case, I think the array stores the names of the meeps, and you should replace ["meep"+i] with ["meep"+meepsarray[i]] (supposing the array contains their serial numbers, not their names).

If the _x values all return numbers, then I don't see why it would not work. You are running your code onenterframe, right? Or in a set interval? Either is good, as long as the code keeps looping.

[Holsey]

Thank you very much koenahn! You set me in the right direction. What i ended up doing is what i was going to do any way, i was just using hittest for testing.

I instead used a distance formula to calculate the distance between each individual meep:

		
		for(var j = 0; j < meepsArray.length; j++){
		Meep.distanceTMX = _level0["meep"+i]._x-_level0["meep"+j]._x;
		Meep.distanceTMY = _level0["meep"+i]._y-_level0["meep"+j]._y;
		Meep.distanceTotTM = Math.sqrt(Meep.distanceTMX * Meep.distanceTMX + Meep.distanceTMY * Meep.distanceTMY);
	
	if(Meep.distanceTotTM < 30 && Meep.distanceTotTM != 0){
trace("success")
}
}

If they're close enough, trace success. This code isn't perfect, in-fact, far from it. But it'll get me started on what i want in the end result. This was the part i was stuck on. Thanks a lot again! You helped me tremendously!

[fruitbeard]

Hi,

This is so similar to what you have ended up with (perhaps even is), but its clever stuff Here

[Holsey]

Hi,

This is so similar to what you have ended up with (perhaps even is), but its clever stuff Here

Oh wow! That helps even more! That's exactly the type of thing i was looking for. Instead what my plan was, if the meeps got close enough, one would just slow down enough so they wouldn't be overlapping. However, this works better. Thank you fruitbeard! Happy holidays and merry christmas all!

[koenahn]

Glad things are workin out for you. Thank you for showing your appreciation.