Break embedded loops simultaneously

[Nialsh]

Does anyone know how to break out of embedded for loops with the same command from the inner loop?
example:

for(i = 0;i < 10;i ++){
	for(n = 0;n < 10;n ++){
		if(myFunction(i,n)){
			//do something
			//break out of both loops
		}
	}
}

I know I could have an extra conditional in the outer loop that checks a variable that gets set by the "if", but that's a lot of extra processing.
Thanks for any help.

[jbum]

Unfortunately, there's no 'goto' command in Flash, although it would come in handy in this case - this is what happens when language designers get overly politically correct.

Here's a few things you could do:

1. Put the whole thing in a function and use return. Costs a little extra for the function call, but possibly not as much as adding a condition to the outer loop.

code:

---

myLoopy = function()

{

  for(i = 0;i < 10;i ++) {

    for(n = 0;n < 10;n ++) {

      if(myFunction(i,n)) {

			//do something

			//break out of both loops

          return;

       }

    }

  }

}

---

2. Use a single loop. Unfortunately, more processor intensive than adding a condition on the outer loop.

code:

---

  for(x = 0;x < 100; x++){

    if (myFunction(Math.floor(x/10),x%10)) {

			//do something

			//break out of both loops

          break;

       }

  }

---

3. Your original suggestion. Probably not that painful, since the bulk of your CPU time happens in the inner loop. This is the choice I'd probably use myself.

code:

---

  over = false;

  for (i = 0; i < 10 && !over; i++) {

    for (n = 0; n < 10; n++) {

      if (myFunction(i,n)) {

			//do something

			//break out of both loops

          over = true;

          break;

       }

    }

  }

---

[Nialsh]

Thanks! I didn't think of putting it in a funciton, but that should work well since I use it twice anyway.

[Antago]

consider also changing the outer loop's variable to something that will break it.
i.e.

for ( i=0; i<40; i++ ) {
    for ( k=0; k<100; k++ ) {
      if (somecondition) {
        i = 40;
        break;
      }
    }
}