Textbox, Strings and Pushing Arrays. Any Ideas?

Hi Bret,
Still trying to get past this text box problem. I've got to this point with help

var correctString="The sad man";
var correctArray=correctString.split(' ');

txt2.onChanged=function(){
var inArray=this.text.split(' ');
var resultArray=new Array();
for(i=0;i<correctArray.length;i++){
if(inArray[i]==correctArray[i]){
resultArray[i]='correct';
gotoandStop(3);
}else{

resultArray[i]=' not correct "' + correctArray[i] +'"-------';
}


}
txt3.text=(resultArray)
}
Selection.setFocus("txt2var");
stop();


But
1. it goes to frame 3 even if only first word is correct should only do it if all correct.
2. how can I not show the incorrect words ie have *** instead of sad?

PS can no one solve the koolmoves exchange menu1 problem - 189 views but only you responding.

Quote:

---

1. it goes to frame 3 even if only first word is correct should only do it if all correct.
2. how can I not show the incorrect words ie have *** instead of sad?

---

var correctString = "The sad man";
var correctArray = correctString.split(' ');

txt2.onChanged = function(){
var inArray = this.text.split(' ');
var resultArray = new Array();
for(i=0;i<correctArray.length;i++){
if(inArray[i] == correctArray[i]){
resultArray[i] = 'correct';
// gotoandStop(3);
}else{
var foo1 = "";
for(j = 0; j < correctArray[i].length; j++){
foo1 += "*";
}
resultArray[i]=' not correct "' + foo1 +'"-------';
}
txt3.text=(resultArray)

}
var foo2 = 0;
for(k = 0;k<resultArray.length;k++){
if(resultArray[k] == 'correct'){
foo2++;
}
}
if(foo2 == resultArray.length){
gotoandStop(3);
}
}
Selection.setFocus("txt2var");
stop();

Thank for this Chris - works great.
If you have the time can you tell me what I did wrong?
Why is the word now ***
thanks to you and Bret for answering this forum
ja

Quote:

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Originally Posted by jarnold

Why is the word now ***

---

You wanted it to display as "***" correct? I went by your wording here:

Quote:

---

2. how can I not show the incorrect words ie have *** instead of sad?

---

You didn't do anything wrong per se. I'll explain what this is doing with comments.....

var correctString = "The sad man";
var correctArray = correctString.split(' ');

txt2.onChanged = function(){
var inArray = this.text.split(' ');
var resultArray = new Array();
for(i=0;i<correctArray.length;i++){
if(inArray[i] == correctArray[i]){
//word typed was correct, push value of 'correct' to resultArray
resultArray[i] = 'correct';
//I removed the line below for use later on
// gotoandStop(3);
}else{
//if we are inside this else clause, the user typed wrong word so we...
//create a foo1 var and initialize it as an empty string always
var foo1 = "";
//we are going to find out the length of the correct word so we can display asterisks that are correct to length
for(j = 0; j < correctArray[i].length; j++){
//create the asterisk replacement which will be the same length as the correct word
foo1 += "*";
}
//build display string as you did in earlier examples but showing the asterisk version NOT the correct word
resultArray[i]=' not correct "' + foo1 +'"-------';
}
//display the string which shows asterisks
txt3.text=(resultArray)

}
//create a foo2 var and initialize it with an integer of zero always
var foo2 = 0;
//check our resultArray to see number of correct words (value of "correct" in array) that have been typed
for(k = 0;k<resultArray.length;k++){
if(resultArray[k] == 'correct'){
//correct word found, increment foo2
foo2++;
}
}
//to finish up the loop we check the foo2 count against the resultArray length. If it matches all words were correct. Step forward in movie.
if(foo2 == resultArray.length){
gotoandStop(3);
}
}
Selection.setFocus("txt2var");
stop();
__________________

Hi Chris,
I meant how does "sad" become "***" (which you've answered). That's a great set of comments for me to learn how to do this. Feel bad having to keep asking you guys.
Thanks again,
John

John we never mind answering well asked questions. I think Chris would agree with me that we enjoy helping that's why we're here. I learn as much as I teach as I usually don't know the answer when people ask but I try to solve it as if it were my own problem and figure it out then share my research, thus learning something new for myself.