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It says math and physics on the forum head...so I figure there must be at least some ppl who know what they're talking about. Why did you even bother posting. Bah.
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Nobody? I really need help, any help is good. I just need to know if I'm on the right track. :yikes:
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Hey guys,
here's the question:
You are an athlete on the high bar in a fully extended position 180 degrees from the right horizontal.
My weight: 667.08N
Center of mass:80.5cm
Radius of...
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Hi,
Ok so we were told to find our center of mass using the reaction board method, but modified. We just do a pushup position with our hands on a scale, I have a electronic one and toes on the...
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Please anyone with any hints? It's really important.
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Ok,
I had to test my maximum vertical jump. I did three trials and here's what I got:
-Maximum standing height (ie without jumping reaching with one hand) = 221.5 cm
-Maximum jumping height with...
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Ah yes, the way you did it is actually right. I went to my prof. It was actually an error on my part, I failed to realize that I had to separate the component forces into Fx and Fy, my bad. Thanks...
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Ok, here's the problem:
Hey,
Ok here's the problem.
A house has a roof with the dimensions in drawing. Determine the magnitude and direction of the net force that the atmosphere applies to...
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I think if we measure antinodes it's half of a full wavelength?
Look at pic?
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Are you sure? The antinodes are the highest point of a wave right, if we were to measure from node to node, the points of no vibration then it'll be one lambda?
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I think you mean 1/3 = time, 3 hz is freq. Ok, the wavelength is equal to ~0.79m. Since the distance isn't really one lambda, but lambda/2, so the distance travelled is ~0.390m. Yes, now I can use...
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Hmm, I might be able to find the distance betwen the two antinodes, it does say it goes from loud-soft-lound. So antinode-node-antinode, and antinode is where it peaks. But find the wavelength...
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Hey,
My question:
Two loudspeakers face each other, vibrate in phase, and produce identical 440Hz tones. A listener walks from one speaker toward the other at a constant speed and hears the...
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Well, with much thought...I figure ok since the mill has 16 blades/gaps, all equal, the theta or angle would be 2pie/16 or pie/8. Using theta=wt, I found the time to be 0.312s.
next, I just used...
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Hey, any ideas on this double starred, hard question :(
A golf ball passing trhough a windmill at a miniature golf course. The windmill has 8 blades and rotates at an angular speed of 1.25 rad/s...
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Ok, I figured out what I did wrong. The quadratic eq for one thing I'm missing a b^2 in the top part. Ok, so now I get 7.0m/s and -4.0m/s. These answers makes more sense because if it is elastic then...
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Ok here's two problems that I have attempted to solve, and quite succesfully, but I need one you to check the work. Suggestions to anyone question is great and well appreciated.
1)A mine car,...
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BTW, Thanks for the Help!
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wow, that looks complicated lol.
Ok, does this way work?
uphill:-mgsin@-F+(E+1298N)
downhill: -mgsin-E+F
solve for E in bottom and sub into uphill equation.
E=-mgsin@+F
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Slosh, help me lol, I'm out of ideas
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Ok is this way possible?
Ok so let me see:
P=FV
P(uphill)=mgsin@ +F(friction)
P(downhill)=mgsin@-F(friction)
ok so I subtract them:
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why did you include 19000 in there might I ask? W acts in the vertical, how does that influence the horizontal forces?
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ok so far so good. Ok so, I don't have F, E and @ variables but I have mg which gives me N?
ok so F=E+X
F=mgsin@
so, mgsin@=E+1298. I can't solve for E, I don't have @.
Ok, so...
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Well as far as understanding your diagram, I'm on the mark. But as for your equations, I'm lost lol. But thanks for the help, I'm sure once I get my sleep/early morning coffee I'll be able to figure...
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