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Thread: cubic equation question

  1. #1
    Junior Member
    Join Date
    May 2002
    Posts
    24
    If I have a function:
    f(x) = 4(x^3) + 150(x^2) + (-126)(x) + 446

    how would I solve for x if f(x)=448 ?

    If it's easier to explain you can just use a generic equation:

    f(x) =A(x^3) + B(x^2) + C(x) + D

    as long as F(x)!=0.

    Thanks,
    Matt

  2. #2
    Junior Member
    Join Date
    Jul 2001
    Posts
    15
    hi
    see http://www.1728.com/cubic2.htm for the solution to cubic equations - just punch your numbers in and follow the trail!

    Hopefully, you'll get one answer that makes sense in the context you're using it.

    hth
    Kuhan

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