Is it possible to have multiple cases in a switch statement

[yvillicana]

Hi,

I made a carousel, which required that I added 44 items in order to get the 15 clips showing on the front plane..However, I only have 10 items which are repeated...
I have a function that uses a switch statement based on the number assigned to the clip---now being that I have only 10 items the different clips in the carousel are arranged like this:
0 is the same as 10 is the same as 20 is the same as 30 is the same as 40.
So, I was wondering if you could do something like this:

			switch (arrcontentNum)
			{
				case 0 || 10 || 20 || 30 || 40:
					//myContent.fade.visible = true;
					myLoadURL = "yahoomessengervistaresizedas3.swf";
					swfX = -275;
					swfY = -183;
					swfZ = swfZholder = 100;
					break;

That doesn't work, do I have to write out all 44 possible case numbers even if there are only 10 clips?

Thanks,
---Yvette

[marlopax]

var arr = 1;

switch (arr) {
    case int(arr) :
        if (arr==1||arr==2||arr==6) {
            common();
        }
        break;
}

function common() {
    var my_value = "Common Value";
    trace(my_value);
} 

OR

var arr = 1;

switch (arr) {
    case 1 :
    case 2 :
    case 6 :
        common();

        break;
}

function common() {
    var my_value = "Common Value";
    trace(my_value); 

[yvillicana]

Nice-Thanks so much!

---Yvette