again, i have some array troubles...

[marmotte]

ok, i have *again* some arrays troubles...

here's an example of what i have:

label = new Array()
label["rrr"] = ["money", "a", "a", "a"];
label["sss"] = ["money", "a", "a", "a"];
label["ttt"] = ["gold", "a", "a", "a"];
label["uuu"] = ["money", "a", "a", "a"];
label["vvv"] = ["gold", "a", "a", "a"];
label["www"] = ["gold", "a", "a", "a"];
label["xxx"] = ["money", "a", "a", "a"];
label["yyy"] = ["gold", "a", "a", "a"];
label["zzz"] = ["silver", "a", "a", "a"];

^ here's a collection of arrays that is quite similar to what i need for my game. the value that i want to work with is the value [0]. in this example, it can be "money", "gold" or "silver".

now, i want to create another array that will sort all these [0] values, and group them depending on this value; so there will be an array holding all the array's names having "money" as [0], another "gold" and another "silver"; as a result, 3 new arrays.
...sorry if it's not clear enough. basically, i want to check the collection of array above and look for all the ones that have "money" as [0] for example.

since i cannot work with a for loop combined with the label.length (because they are not called label[0], label[1], label[2] etc... the length isn't working), how can i do that?

> my solution is to have another array holding all "rrr", "sss", "ttt" ... "zzz" values and perform a for loop thanks to it. something like that:

label_check = ["rrr", "sss", "ttt" ... "zzz"];

BUT i have something like 40/50 arrays each time, so sorry i absolutely don't want to rewrite them all that way!!! ^^

is there a solution? thanks a lot if you can help...

[mbenney]

something like this might do?

code:

---

label = new Array()

label["rrr"] = ["money", "a", "a", "a"];

label["sss"] = ["money", "a", "a", "a"];

label["ttt"] = ["gold", "a", "a", "a"];

label["uuu"] = ["money", "a", "a", "a"];

label["vvv"] = ["gold", "a", "a", "a"];

label["www"] = ["gold", "a", "a", "a"];

label["xxx"] = ["money", "a", "a", "a"];

label["yyy"] = ["gold", "a", "a", "a"];

label["zzz"] = ["silver", "a", "a", "a"];



money = new Array();

gold = new Array();

silver = new Array();



for(i in label) {

	if(label[i][0] == "money") {

		money.push(label[i])

	} else if (label[i][0] == "gold") {

		gold.push(label[i])

	} else {

		silver.push(label[i])

	}

}

trace(money)

trace(gold)

trace(silver)

---

[m]

[marmotte]

!!!of course!!!

where was my head? i was so concentrated with the for loop that i forgot to test or think about the for...in loop! duh!
thanks a lot mbenney, i'll try it tomorrow... (sure, it has to work like that). it's a LOT of time saving for me here, wow.

again, thanks.

[mbenney]

np matey =)